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PUCET (Punjab) Wave Optics — practice questions — page 2

Explore 71 free Wave Optics questions in PUCET (Punjab) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Wave Optics questions and exercises with answers

Showing questions 31–60 of 71.

In a thin film of thickness t with refractive index n, condition for destructive interference for reflected light (no phase change on reflection conditions):Read the answer and worked solution →Diffraction is the:Read the answer and worked solution →Single-slit diffraction first minimum occurs at angle θ where:Read the answer and worked solution →Brewster's angle θ_B for light hitting glass (n = 1.5) from air satisfies:Read the answer and worked solution →For maximum brightness in Newton's rings (reflected light, air film), what is the radius of n-th bright ring? (R = lens radius, λ = wavelength)Read the answer and worked solution →Two slits 0.5 mm apart with light of wavelength 5000 Å. The 5th bright fringe is at distance from central maximum on screen 1 m away:Read the answer and worked solution →In Young's experiment, if the entire setup is immersed in water (n = 4/3), the fringe width:Read the answer and worked solution →Power of a convex lens of focal length 50 cm:Read the answer and worked solution →Resolution limit of a telescope by Rayleigh criterion:Read the answer and worked solution →Wavelength of light in water (n = 4/3) if its vacuum wavelength is 600 nm:Read the answer and worked solution →Two coherent sources have intensities I1 = 9I and I2 = I. Maximum and minimum intensities in interference pattern:Read the answer and worked solution →In Young's experiment, intensity at a point where path difference is λ/4:Read the answer and worked solution →For a grating with 500 lines/mm and light at 600 nm, find angle for the first-order maximum:Read the answer and worked solution →In single-slit diffraction, ratio of intensities of first and central maxima is approximately:Read the answer and worked solution →Speed of light in a medium of refractive index 1.5 is:Read the answer and worked solution →A wavefront is:Read the answer and worked solution →Young's double-slit experiment demonstrates:Read the answer and worked solution →For constructive interference, path difference Δp =Read the answer and worked solution →In YDSE, fringe width β =Read the answer and worked solution →Coherent sources have:Read the answer and worked solution →In YDSE with λ = 600 nm, d = 0.2 mm, D = 1 m, fringe width =Read the answer and worked solution →Diffraction is:Read the answer and worked solution →Single-slit diffraction first minimum at angle θ satisfies:Read the answer and worked solution →Polarization establishes that light is:Read the answer and worked solution →Brewster's law: angle of polarization i_B from glass-air interface satisfies:Read the answer and worked solution →Maximum number of bright fringes visible in YDSE with d/λ = 4:Read the answer and worked solution →Speed of light in a medium of refractive index n =Read the answer and worked solution →Resolving power of a microscope is proportional to:Read the answer and worked solution →In YDSE with monochromatic light (λ = 500 nm) and d = 0.1 mm, distance from central maximum to 3rd bright fringe on screen at D = 2 m:Read the answer and worked solution →In YDSE, when whole apparatus is immersed in water (n = 4/3), fringe width:Read the answer and worked solution →

Worked practice questions

In a thin film of thickness t with refractive index n, condition for destructive interference for reflected light (no phase change on reflection conditions):

  1. 2nt = nλ
  2. 2nt = (m + 1/2)λ
  3. 2nt = mλ
  4. nt = mλ
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Correct answer: C. 2nt = mλ

For a thin film with one phase change of pi at reflection from denser medium, destructive interference: 2nt = mλ for m = 0, 1, 2, ... This is why soap bubbles show coloured patterns.

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Diffraction is the:

  1. Splitting of light into colours
  2. Bending of waves around obstacles or at apertures
  3. Total reflection
  4. Polarization
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Correct answer: B. Bending of waves around obstacles or at apertures

Diffraction is the bending of waves around obstacles or through apertures, more pronounced when obstacle size is comparable to wavelength. All wave phenomena (light, sound, water waves) exhibit diffraction.

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Single-slit diffraction first minimum occurs at angle θ where:

  1. a sin θ = λ
  2. a sin θ = 2λ
  3. 2a sin θ = λ
  4. a cos θ = λ
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Correct answer: A. a sin θ = λ

For single-slit diffraction of slit width a: first minimum at a sin θ = λ. Higher-order minima at a sin θ = 2λ, 3λ, etc.

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