Wavelength of light in water (n = 4/3) if its vacuum wavelength is 600 nm:
A450 nm
B600 nm
C800 nm
D900 nm
Answer & Solution
Correct answer: A. 450 nm
λ_medium = λ_vacuum / n = 600/(4/3) = 600 × 3/4 = 450 nm. Frequency stays the same; wavelength shrinks in denser media.
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