In YDSE, when whole apparatus is immersed in water (n = 4/3), fringe width:
ABecomes 0
BDoubled
CUnchanged
DDecreased by factor of n (= 4/3): β_water = β_air × 3/4
Answer & Solution
Correct answer: D. Decreased by factor of n (= 4/3): β_water = β_air × 3/4
Wavelength in water = λ₀/n. Fringe width β = λD/d → β_water = β_air/n = (3/4) β_air. Fringes get closer.
Related questions
Blue sky seen through a rotating polaroid rises and falls in brightness. Sky light is:Two polaroids are set crossed. The light passing through both is:Ordinary lamp light passes through one polaroid. Its intensity drops to:Wiggle a string up and down and a wave runs along it. The displacement is at right angles The rainbow of colours you see on a CD comes from:Diffraction is shown by:Near the edge of a shadow you see alternate dark and bright bands. This is:In Young's pattern, consecutive bright fringes are: