Two slits 0.5 mm apart with light of wavelength 5000 Å. The 5th bright fringe is at distance from central maximum on screen 1 m away:
A2.5 mm
B5 mm
C7.5 mm
D10 mm
Answer & Solution
Correct answer: B. 5 mm
Position of n-th bright fringe: y_n = n λ D/d = 5 × (5000 × 10⁻¹⁰) × 1 / (0.5 × 10⁻³) = 5 × 10⁻³ m = 5 mm.
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