In YDSE with monochromatic light (λ = 500 nm) and d = 0.1 mm, distance from central maximum to 3rd bright fringe on screen at D = 2 m:
A0.3 mm
B30 mm
C15 mm
D3 mm
Answer & Solution
Correct answer: B. 30 mm
β = λD/d = (500 × 10⁻⁹)(2)/(0.1 × 10⁻³) = 10⁻² m = 10 mm. 3rd bright at 3β = 30 mm.
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