In YDSE with monochromatic light (λ = 500 nm) and d = 0.1 mm, distance…

Question

In YDSE with monochromatic light (λ = 500 nm) and d = 0.1 mm, distance from central maximum to 3rd bright fringe on screen at D = 2 m:

Accepted Answer

B. 30 mm

We have β = λD/d.
That is β = (500 × 10⁻⁹)(2)/(0.1 × 10⁻³).
That is β = 10⁻² m.
So β = 10 mm.
3rd bright at 3β = 30 mm.

Answer

0.3 mm

Answer

15 mm

Answer

3 mm

In YDSE with monochromatic light (λ = 500 nm) and d = 0.1 mm, distance from central maximum to 3rd bright fringe on screen at D = 2 m: