alleryIn Young's experiment, intensity at a point where path difference is λ/4:
AI_max
BI_max/2
CI_max/4
DZero
Answer & Solution
Correct answer: B. I_max/2
Phase difference δ = (2π/λ)(λ/4) = π/2. Intensity I = I_max cos²(δ/2) = I_max cos²(π/4) = I_max (1/2) = I_max/2.
Keep practising Wave Optics
Browse all Wave Optics questions for JEE Advanced, or explore more Physics topics.
Related questions
Polarisation of light is direct experimental evidence that light is a:The resolving power (RP) of a diffraction grating with N slits in the m-th order is:In Young's double-slit experiment, the fringe width β is given by:In Young's experiment, a BRIGHT fringe (constructive interference) requires path differencIn single-slit diffraction, the central maximum is:BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:HUYGENS' PRINCIPLE states that every point on a wavefront acts as a:Light passes from air to glass ($n = 1.5$). Brewster's angle is: