Practice free →
HomeJEE MainPhysicsWave Optics › In Young's experiment, intensity at a point wher…

In Young's experiment, intensity at a point where path difference is λ/4:

AI_max
BI_max/2
CI_max/4
DZero
Answer & Solution
Correct answer: B. I_max/2
Phase difference δ = (2π/λ)(λ/4) = π/2. Intensity I = I_max cos²(δ/2) = I_max cos²(π/4) = I_max (1/2) = I_max/2.
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions