Maximum number of bright fringes visible in YDSE with d/λ = 4:
A8
BInfinite
C4
D9 (m from -4 to +4, since |sin θ| ≤ 1)
Answer & Solution
Correct answer: D. 9 (m from -4 to +4, since |sin θ| ≤ 1)
Condition: d sin θ = m λ requires |m| ≤ d/λ = 4. So m = -4, -3, ..., 3, 4 → 9 fringes.
Keep practising Wave Optics
Browse all Wave Optics questions for JEE Advanced, or explore more Physics topics.
Related questions
Polarisation of light is direct experimental evidence that light is a:The resolving power (RP) of a diffraction grating with N slits in the m-th order is:In Young's double-slit experiment, the fringe width β is given by:In Young's experiment, a BRIGHT fringe (constructive interference) requires path differencIn single-slit diffraction, the central maximum is:BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:HUYGENS' PRINCIPLE states that every point on a wavefront acts as a:Light passes from air to glass ($n = 1.5$). Brewster's angle is: