For a grating with 500 lines/mm and light at 600 nm, find angle for the first-order maximum:
Asin⁻¹(0.3)
Bsin⁻¹(0.5)
Csin⁻¹(0.6)
Dsin⁻¹(0.9)
Answer & Solution
Correct answer: A. sin⁻¹(0.3)
Slit spacing d = 1/500 mm = 2 μm. For first order: d sin θ = λ. sin θ = 600 × 10⁻⁹ / (2 × 10⁻⁶) = 0.3. So θ = sin⁻¹(0.3).
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