Start learning →

For a grating with 500 lines/mm and light at 600 nm, find angle for the first-order maximum:

Asin⁻¹(0.3)
Bsin⁻¹(0.5)
Csin⁻¹(0.6)
Dsin⁻¹(0.9)
Answer & Solution
Correct answer: A. sin⁻¹(0.3)
Slit spacing d = 1/500 mm = 2 μm. **For first order:** d sin θ = λ. sin θ = 600 × 10⁻⁹ / (2 × 10⁻⁶) = 0.3. So θ = sin⁻¹(0.3).
Practise this question with Quill — JEE Advanced →

Keep practising Wave Optics

Browse all Wave Optics questions for JEE Advanced, or explore more Physics topics.

Start a Wave Optics lesson →