Brewster's law: angle of polarization i_B from glass-air interface satisfies:
Acos i_B = n
Btan i_B = n (refractive index)
Csin i_B = n
Di_B = 45°
Answer & Solution
Correct answer: B. tan i_B = n (refractive index)
At Brewster's angle, reflected light is completely polarized (E perpendicular to plane of incidence). tan i_B = n. For glass (n = 1.5): i_B ≈ 56.3°. Reflected and refracted rays are perpendicular at this angle.
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