In YDSE with λ = 600 nm, d = 0.2 mm, D = 1 m, fringe width =
A3 mm (β = 600 × 10⁻⁹ × 1 / 0.2 × 10⁻³)
B0.3 mm
C6 mm
D1 mm
Answer & Solution
Correct answer: A. 3 mm (β = 600 × 10⁻⁹ × 1 / 0.2 × 10⁻³)
β = λD/d = (600 × 10⁻⁹)(1)/(0.2 × 10⁻³) = 3 × 10⁻³ m = 3 mm.
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