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PUCET (Punjab) Optics — practice questions

Explore 89 free Optics questions in PUCET (Punjab) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Optics questions and exercises with answers

Showing questions 1–30 of 89.

Newton's FIRST law is also called the law of:Read the answer and worked solution →Newton's SECOND law states:Read the answer and worked solution →The SI unit of force is the:Read the answer and worked solution →Frictional force between surfaces ALWAYS acts:Read the answer and worked solution →Static friction f_s satisfies:Read the answer and worked solution →Kinetic friction f_k is given by:Read the answer and worked solution →For a body on a horizontal surface, the NORMAL FORCE N equals:Read the answer and worked solution →In circular motion at radius r and speed v, the centripetal acceleration is:Read the answer and worked solution →The ANGLE OF REPOSE φ is related to coefficient of friction by:Read the answer and worked solution →A 5 kg object experiences a net force of 20 N. Find its acceleration:Read the answer and worked solution →A 10 kg block on rough horizontal surface with μ_s = 0.3 just starts moving. Force applied:Read the answer and worked solution →A block of mass 2 kg on a smooth incline at 30°. Acceleration down the incline (g = 10):Read the answer and worked solution →A 1500 kg car accelerates from 0 to 30 m/s in 10 s. Average force on car:Read the answer and worked solution →In a tug-of-war, team A pulls with 200 N, team B pulls oppositely with 250 N. The rope (light) experiences net force:Read the answer and worked solution →A block of mass 5 kg on a rough incline at 37° with μ_k = 0.4. Acceleration down (g = 10, sin 37° = 0.6, cos 37° = 0.8):Read the answer and worked solution →For a body on a 60° incline with μ = 0.5, the body:Read the answer and worked solution →An object's WEIGHT on Earth (g = 10) is 50 N. Its MASS is:Read the answer and worked solution →A 5 kg block is pushed with 30 N along a frictionless surface. Acceleration:Read the answer and worked solution →A massless pulley system has two blocks: m₁ = 6 kg and m₂ = 4 kg hanging on either side. Find acceleration of system (g = 10):Read the answer and worked solution →The angle of repose between a block and an incline is 30°. The coefficient of static friction is:Read the answer and worked solution →A 100 g object is moving in a vertical circle. At the TOP of the loop, for minimum speed (string just slack), v_min equals:Read the answer and worked solution →Limiting (max static) friction is INDEPENDENT of:Read the answer and worked solution →A 4 kg mass hangs from a spring scale in an elevator. Spring reads 32 N. The elevator is:Read the answer and worked solution →A 3 kg block is pulled with F = 20 N at 30° above horizontal on rough surface (μ_k = 0.4). Find acceleration (g = 10, sin 30° = 0.5, cos 30° = 0.866):Read the answer and worked solution →In a uniform circular motion, the SPEED is constant but velocity changes direction. The acceleration:Read the answer and worked solution →A car turns a corner of radius 50 m at 20 m/s. Minimum coefficient of friction needed (g = 10):Read the answer and worked solution →A 50 kg person stands on a scale in an elevator accelerating UP at 2 m/s². Scale reading:Read the answer and worked solution →Two equal masses (3 kg each) connected by a light string over a frictionless pulley. One on smooth horizontal table, other hangs over edge. Acceleration?Read the answer and worked solution →A pendulum of mass m swings to amplitude angle θ. At the lowest point of swing, the TENSION in the string equals:Read the answer and worked solution →A car of mass 1000 kg moving at 36 km/h is stopped by brakes in 5 seconds. Average force exerted by brakes:Read the answer and worked solution →

Worked practice questions

Newton's FIRST law is also called the law of:

  1. Inertia
  2. Action and reaction
  3. Gravity
  4. Friction
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Correct answer: A. Inertia

Law of Inertia: An object at rest stays at rest, and an object in motion stays in motion at constant velocity, unless acted upon by an unbalanced external force.

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Newton's SECOND law states:

  1. F = mv
  2. F = ma (net force = mass × acceleration)
  3. F = ½mv²
  4. F = mgh
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Correct answer: B. F = ma (net force = mass × acceleration)

Net force on an object equals its mass times its acceleration: F⃗ = ma⃗. The direction of acceleration is the same as net force. **SI unit of force:** newton (1 N = 1 kg·m/s²).

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The SI unit of force is the:

  1. joule
  2. newton
  3. watt
  4. pascal
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Correct answer: B. newton

Newton (N). 1 N = 1 kg·m/s² — the force that gives a 1 kg mass an acceleration of 1 m/s².

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