alleryIn Young's experiment, if the entire setup is immersed in water (n = 4/3), the fringe width:
ASame
BIncreases by factor 4/3
CDecreases by factor 4/3
DDoubles
Answer & Solution
Correct answer: C. Decreases by factor 4/3
Wavelength in water becomes λ/n.
**So fringe width β = λD/(nd) = β_air/n = β_air × 3/4. Fringes become closer (smaller width).**
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