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NEET UG Electromagnetism — practice questions

Explore 22 free Electromagnetism questions in NEET UG Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electromagnetism questions and exercises with answers

Showing questions 1–22 of 22.

The magnetic force on a charge q moving with velocity v in magnetic field B is:Read the answer and worked solution →Magnetic force on a current-carrying conductor of length L in magnetic field B is:Read the answer and worked solution →A charge q moves perpendicular to a uniform magnetic field B with speed v. The radius of its circular path is:Read the answer and worked solution →Biot-Savart law for the magnetic field due to a small current element I dL at point r is:Read the answer and worked solution →The magnetic field inside a long straight solenoid with n turns per unit length carrying current I is approximately:Read the answer and worked solution →Torque on a magnetic dipole (current loop) of moment m placed in a uniform field B at angle θ is:Read the answer and worked solution →A cyclotron of magnetic field B accelerates positive charges of mass m, charge q. The cyclotron frequency is:Read the answer and worked solution →The dimensional formula of the magnetic field B (in SI units of tesla) is:Read the answer and worked solution →Magnetic field at a point on the axis of a circular loop, far from the loop (distance x ≫ R), behaves as:Read the answer and worked solution →The work done by a static magnetic force on a moving charge is:Read the answer and worked solution →A galvanometer is converted into an ammeter of higher range by connecting:Read the answer and worked solution →An electron and a proton enter a magnetic field with the same kinetic energy, perpendicular to B. The ratio of radii r_e / r_p is:Read the answer and worked solution →Coulomb's law gives the force between two point charges q₁ and q₂ separated by distance r in vacuum asRead the answer and worked solution →Two point charges of +2 μC each are placed 3 m apart in vacuum. The force between them is (k = 9 × 10⁹ N m²/C²)Read the answer and worked solution →The electric field at distance r from an isolated point charge q isRead the answer and worked solution →The electric field of an infinite line of charge with linear charge density λ at perpendicular distance r isRead the answer and worked solution →The electric field just outside a uniformly charged infinite plane with surface charge density σ isRead the answer and worked solution →Gauss's law states that the total electric flux through a closed surface equalsRead the answer and worked solution →An electric dipole consists of two equal and opposite point charges ±q separated by distance 2a. Its dipole moment magnitude isRead the answer and worked solution →The electric field on the axial line of a short electric dipole at distance r isRead the answer and worked solution →The electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻¹² C²/N m²)Read the answer and worked solution →For a charge distribution with volume density ρ, the total charge Q equalsRead the answer and worked solution →

Worked practice questions

The magnetic force on a charge q moving with velocity v in magnetic field B is:

  1. F = q v · B
  2. F = q B
  3. F = q v × B
  4. F = q (v + B)
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Correct answer: C. F = q v × B

1. Lorentz magnetic force: F = q v × B (cross product). 2. Magnitude: F = q v B sinθ. Maximum at θ = 90°, zero when v ∥ B. 3. Direction by right-hand rule. Force is ⊥ to both v and B. _Source: syllabus Physics Ch 4 §4.2 Magnetic Force_

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Magnetic force on a current-carrying conductor of length L in magnetic field B is:

  1. F = I L · B
  2. F = I L × B
  3. F = I L + B
  4. F = I L / B
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Correct answer: B. F = I L × B

1. F = I L × B (vector); magnitude F = I L B sinθ. 2. L is taken along the direction of current flow. 3. This is the basis of motors and current-balance experiments. _Source: syllabus Physics Ch 4 §4.4 Force on a Current-Carrying Conductor_

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A charge q moves perpendicular to a uniform magnetic field B with speed v. The radius of its circular path is:

  1. r = m B / (q v)
  2. r = q B / (m v)
  3. r = q v / (m B)
  4. r = m v / (q B)
Show answer and solution

Correct answer: D. r = m v / (q B)

1. Magnetic force = centripetal force: q v B = m v² / r. 2. r = m v / (q B). 3. The period T = 2π m / (q B) is INDEPENDENT of v (cyclotron principle). _Source: syllabus Physics Ch 4 §4.3 Motion in a Magnetic Field_

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More Physics topics

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