A cyclotron of magnetic field B accelerates positive charges of mass m, charge q. The cyclotron frequency is:
Af = q² B / m
Bf = m / (q B)
Cf = q B / m
Df = q B / (2π m)
Answer & Solution
Correct answer: D. f = q B / (2π m)
1. Period T = 2π m / (q B); frequency f = 1/T = q B / (2π m).
2. Crucially f is INDEPENDENT of velocity v — that's why the cyclotron works.
3. AC voltage between the dees is tuned to this frequency for resonance.
_Source: NCERT Class 12 Physics Ch 4 §4.3 Cyclotron_
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