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NEET UG Electric Charges and Fields — practice questions

Explore 189 free Electric Charges and Fields questions in NEET UG Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electric Charges and Fields questions and exercises with answers

Showing questions 1–30 of 189.

If 10⁹ electrons leave a body every second, the time required to accumulate a total charge of 1 C is approximately:Read the answer and worked solution →The electric field on the **equatorial line** of a dipole (perpendicular bisector, r >> a) has magnitude:Read the answer and worked solution →If a point charge is placed **outside** a closed Gaussian surface, the total flux through the surface is:Read the answer and worked solution →Electric potential is a:Read the answer and worked solution →An equipotential surface is perpendicular to:Read the answer and worked solution →Capacitance of a parallel-plate capacitor is:Read the answer and worked solution →Energy stored in a capacitor equals:Read the answer and worked solution →Capacitors in series share:Read the answer and worked solution →Time constant of an RC circuit is:Read the answer and worked solution →The smallest charge that can exist freely in nature isRead the answer and worked solution →An electric dipole of dipole moment $\vec{p}$ is placed in a UNIFORM electric field $\vec{E}$. The torque experienced isRead the answer and worked solution →The electric field at a distance $r$ from a POINT charge $q$ (in vacuum) has magnitudeRead the answer and worked solution →The SI unit of electric potential isRead the answer and worked solution →Electric potential at infinity in the standard syllabus convention is taken asRead the answer and worked solution →The SI unit of capacitance isRead the answer and worked solution →Electric field at any point inside a hollow charged conductor isRead the answer and worked solution →On an equipotential surface, the work done in moving a test charge between any two points isRead the answer and worked solution →The potential at a distance 0.30 m from a point charge of +20 nC is (k = 9 × 10⁹ N m² C⁻²)Read the answer and worked solution →A parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance isRead the answer and worked solution →Three capacitors of 2 µF each are connected in series. The equivalent capacitance isRead the answer and worked solution →The work done in bringing a charge q from infinity to a point where the potential is V isRead the answer and worked solution →Two capacitors of 4 µF and 6 µF are connected in parallel and charged by a 10 V battery. The total charge stored isRead the answer and worked solution →When the separation between the plates of an air parallel-plate capacitor is doubled (keeping plate area constant), the capacitanceRead the answer and worked solution →An electric dipole of moment p is placed in a uniform field E. The work done to rotate it from the orientation θ = 0 (aligned with the field) to θ = 180° isRead the answer and worked solution →A 5 µF capacitor is charged to 200 V. The energy stored in it isRead the answer and worked solution →An isolated conducting sphere of radius R carries a charge Q. The electric potential at its centre is (V(∞) = 0)Read the answer and worked solution →Four equal point charges q sit at the corners of a square of side d. The work needed to assemble this configuration from infinity isRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Coulomb's Law — Gap FillRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Quantity to UnitRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Conductor or InsulatorRead the answer and worked solution →

Worked practice questions

If 10⁹ electrons leave a body every second, the time required to accumulate a total charge of 1 C is approximately:

  1. 200 days
  2. 200 hours
  3. 200 years (≈ 6.25 × 10⁹ seconds)
  4. 2 hours
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Correct answer: C. 200 years (≈ 6.25 × 10⁹ seconds)

**Charge per second:** 10⁹ × 1.6 × 10⁻¹⁹ = 1.6 × 10⁻¹⁰ C/s. **Time for 1 C:** 1 / (1.6 × 10⁻¹⁰) = 6.25 × 10⁹ s = 6.25 × 10⁹ / (365 × 24 × 3600) ≈ **198 years ≈ 200 years**. Shows 1 C is a very large unit for electrostatics.

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The electric field on the **equatorial line** of a dipole (perpendicular bisector, r >> a) has magnitude:

  1. 2kp/r³
  2. kp/r³, direction **antiparallel** to the dipole moment p
  3. kp²/r³
  4. kp/(r² + a²)^(3/2)
Show answer and solution

Correct answer: B. kp/r³, direction **antiparallel** to the dipole moment p

**Equatorial dipole field at large r**: E = kp/r³ pointing **opposite to p** (because both charge fields contribute components antiparallel to p; the parallel-to-r components cancel by symmetry). E_eq is **half** of E_axial in magnitude.

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If a point charge is placed **outside** a closed Gaussian surface, the total flux through the surface is:

  1. q/ε₀
  2. Zero - no enclosed charge
  3. q/2ε₀
  4. Depends on the shape
Show answer and solution

Correct answer: B. Zero - no enclosed charge

**Charge outside → q_enclosed = 0 → Φ = 0** (Gauss's law). However, the **electric field at points on the surface is NOT zero** (external charges still contribute E). The integral of E · dA over the closed surface vanishes because every field line that enters must exit.

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