The electric flux through a closed surface enclosing a charge of +5 μC…

Question

The electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻¹² C²/N m²)

Accepted Answer

D. {'text': '5.65 × 10⁵ N m²/C', 'label': 'D'}

1. By Gauss's law, Φ = Q_enc / ε₀.
2. Substitute: Φ = 5 × 10⁻⁶ / 8.85 × 10⁻¹².
3. = 5.65 × 10⁵ N·m²/C.
4. Result is independent of the shape of the closed surface.
_Source: NCERT Class 12 Physics, Ch 1 "Electric Charges and Fields", §1.9_

Answer

{'text': '5 × 10⁵ N m²/C', 'label': 'A'}

Answer

{'text': '1.77 × 10⁴ N m²/C', 'label': 'B'}

Answer

{'text': '4.42 × 10⁻⁶ N m²/C', 'label': 'C'}