alleryThe electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻¹² C²/N m²)
A5 × 10⁵ N m²/C
B1.77 × 10⁴ N m²/C
C4.42 × 10⁻⁶ N m²/C
D5.65 × 10⁵ N m²/C
Answer & Solution
Correct answer: D. 5.65 × 10⁵ N m²/C
1. By Gauss's law, Φ = Q_enc / ε₀.
2. Substitute: Φ = 5 × 10⁻⁶ / 8.85 × 10⁻¹².
3. = 5.65 × 10⁵ N·m²/C.
4. Result is independent of the shape of the closed surface.
_Source: syllabus Physics, Ch 1 "Electric Charges and Fields", §1.9_
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