alleryBiot-Savart law for the magnetic field due to a small current element I dL at point r is:
AdB = (μ₀/4π) I (dL × r̂) / r²
BdB = (μ₀/4π) I (dL · r̂) / r²
CdB = (μ₀/4π) I dL / r
DdB = (μ₀/4π) I dL × r
Answer & Solution
Correct answer: A. dB = (μ₀/4π) I (dL × r̂) / r²
1. dB = (μ₀/4π) · I dL × r̂ / r².
2. r̂ is the unit vector from the source element to the field point.
3. The 1/r² dependence parallels Coulomb's law in electrostatics.
_Source: syllabus Physics Ch 4 §4.5 Biot-Savart Law_
Keep practising Electromagnetism
Browse all Electromagnetism questions for NEET UG, or explore more Physics topics.
Related questions
For a charge distribution with volume density ρ, the total charge Q equalsThe electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻The electric field on the axial line of a short electric dipole at distance r isAn electric dipole consists of two equal and opposite point charges ±q separated by distanGauss's law states that the total electric flux through a closed surface equalsThe electric field just outside a uniformly charged infinite plane with surface charge denThe electric field of an infinite line of charge with linear charge density λ at perpendicThe electric field at distance r from an isolated point charge q is