The electric field just outside a uniformly charged infinite plane with surface charge density σ is
Aσ / (2 ε₀)
Bσ / ε₀
Cσ ε₀
D2 σ / ε₀
Answer & Solution
Correct answer: A. σ / (2 ε₀)
1. Use Gauss's law with a pillbox spanning the sheet.
2. Field E is perpendicular to the sheet, equal on both sides by symmetry.
3. Flux = 2 E A = σ A / ε₀, so E = σ / (2 ε₀).
4. This is a uniform field, independent of distance from the sheet.
_Source: syllabus Physics, Ch 1 "Electric Charges and Fields", §1.11_
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