alleryMagnetic force on a current-carrying conductor of length L in magnetic field B is:
AF = I L · B
BF = I L × B
CF = I L + B
DF = I L / B
Answer & Solution
Correct answer: B. F = I L × B
1. F = I L × B (vector); magnitude F = I L B sinθ.
2. L is taken along the direction of current flow.
3. This is the basis of motors and current-balance experiments.
_Source: syllabus Physics Ch 4 §4.4 Force on a Current-Carrying Conductor_
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