A charge q moves perpendicular to a uniform magnetic field B with speed v. The radius of its circular path is:
Ar = m B / (q v)
Br = q B / (m v)
Cr = q v / (m B)
Dr = m v / (q B)
Answer & Solution
Correct answer: D. r = m v / (q B)
1. Magnetic force = centripetal force: q v B = m v² / r.
2. r = m v / (q B).
3. The period T = 2π m / (q B) is INDEPENDENT of v (cyclotron principle).
_Source: NCERT Class 12 Physics Ch 4 §4.3 Motion in a Magnetic Field_
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