The electric field at distance r from an isolated point charge q is
AE = kq / r
BE = kq × r
CE = kq / r²
DE = kq × r²
Answer & Solution
Correct answer: C. E = kq / r²
1. Electric field is force per unit test charge.
2. From Coulomb's law: E = F/q_test = k q / r².
3. Direction is radially outward for positive q, inward for negative.
4. SI unit is N/C or equivalently V/m.
_Source: syllabus Physics, Ch 1 "Electric Charges and Fields", §1.6_
Keep practising Electromagnetism
Browse all Electromagnetism questions for JEE Advanced, or explore more Physics topics.
Related questions
For a charge distribution with volume density ρ, the total charge Q equalsThe electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻The electric field on the axial line of a short electric dipole at distance r isAn electric dipole consists of two equal and opposite point charges ±q separated by distanGauss's law states that the total electric flux through a closed surface equalsThe electric field just outside a uniformly charged infinite plane with surface charge denThe electric field of an infinite line of charge with linear charge density λ at perpendicTwo point charges of +2 μC each are placed 3 m apart in vacuum. The force between them is