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JEE Main Unit 2B1: Transition Metals & Coordination Compounds — practice questions

Explore 61 free Unit 2B1: Transition Metals & Coordination Compounds questions in JEE Main Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 2B1: Transition Metals & Coordination Compounds questions and exercises with answers

Showing questions 1–30 of 61.

In a coordination compound, the central atom is usually:Read the answer and worked solution →Coordination number is:Read the answer and worked solution →In [Cu(NH3)4]²⁺ what is the oxidation number of Cu?Read the answer and worked solution →What is the coordination number in [Co(NH3)6]³⁺?Read the answer and worked solution →What is the geometry of complex with coordination number 6 typically?Read the answer and worked solution →What is the geometry of [Ni(CN)4]²⁻?Read the answer and worked solution →Crystal Field Theory: in an OCTAHEDRAL field, the d-orbitals split into:Read the answer and worked solution →Spectrochemical series (ligand strength): which is a STRONG-field ligand?Read the answer and worked solution →Which type of isomerism arises when two ligands can bind through different donor atoms (e.g., NO2⁻ via N vs O)?Read the answer and worked solution →Cis and trans isomers of [Co(NH3)4Cl2]⁺ are examples of:Read the answer and worked solution →Which complex is paramagnetic?Read the answer and worked solution →EDTA is a:Read the answer and worked solution →The complex [Fe(CN)6]⁴⁻ is:Read the answer and worked solution →In strong-field octahedral, electron filling order in d-orbitals follows:Read the answer and worked solution →Oxidation state of Co in [Co(NH3)5Cl]Cl2:Read the answer and worked solution →Number of geometric isomers of [Pt(NH3)2Cl2] (square planar):Read the answer and worked solution →For octahedral d6 with weak-field ligands (high-spin), number of unpaired electrons:Read the answer and worked solution →For octahedral d6 with STRONG-field ligands (low-spin), number of unpaired electrons:Read the answer and worked solution →Number of unpaired electrons in [FeF6]³⁻ (high-spin, F⁻ weak-field):Read the answer and worked solution →Hybridization in [Ni(CO)4] (Ni is 0 oxidation state, sp3 because CO is strong-field for Ni⁰):Read the answer and worked solution →For [Cr(H2O)6]³⁺, d-electron count and magnetic behavior:Read the answer and worked solution →Which one is an ambidentate ligand?Read the answer and worked solution →For octahedral [Mn(H2O)6]²⁺, d-electron count and unpaired e⁻ count:Read the answer and worked solution →Name of complex K3[Fe(CN)6]:Read the answer and worked solution →For [Cu(NH3)4(H2O)2]²⁺ (octahedral with 4 NH3 equatorial + 2 H2O axial), this is:Read the answer and worked solution →In coordination compound [Cu(NH₃)₄]SO₄, the central metal is:Read the answer and worked solution →Coordination number of a metal is:Read the answer and worked solution →Denticity of a ligand refers to:Read the answer and worked solution →Werner's coordination theory introduced primary and secondary valencies. Primary valency corresponds to:Read the answer and worked solution →Oxidation state of Cr in [Cr(NH₃)₆]Cl₃:Read the answer and worked solution →

Worked practice questions

In a coordination compound, the central atom is usually:

  1. An anion
  2. A transition metal cation or neutral atom
  3. A noble gas
  4. A non-metal
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Correct answer: B. A transition metal cation or neutral atom

The central atom or ion in a coordination complex is typically a transition metal cation (which can accept multiple lone pairs into d-orbitals). **Examples:** Co³⁺, Fe²⁺, Cu²⁺, Ni²⁺.

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Coordination number is:

  1. Number of donor atoms directly bonded to central metal
  2. Charge on metal
  3. Number of electrons
  4. Number of ligands
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Correct answer: A. Number of donor atoms directly bonded to central metal

Coordination number = number of donor atoms (not ligands!) directly bonded to the metal. For polydentate ligands, one ligand contributes multiple donor atoms. **Typical CN:** 4 (tetrahedral/square planar), 6 (octahedral).

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In [Cu(NH3)4]²⁺ what is the oxidation number of Cu?

  1. +3
  2. +2
  3. +1
  4. 0
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Correct answer: B. +2

NH3 is neutral. Complex charge is +2. So Cu oxidation state = +2 + 0 - 0 = +2. (Cu²⁺ ion with 4 NH3 ligands.)

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