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In [Cu(NH3)4]²⁺ what is the oxidation number of Cu?
A+3
B+2
C+1
D0
Answer & Solution
Correct answer: B. +2
NH3 is neutral. Complex charge is +2. So Cu oxidation state = +2 + 0 - 0 = +2. (Cu²⁺ ion with 4 NH3 ligands.)
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