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For [Cr(H2O)6]³⁺, d-electron count and magnetic behavior:
Ad⁰, diamagnetic
Bd⁵, paramagnetic
Cd³, paramagnetic with 3 unpaired e⁻
Dd⁶, diamagnetic
Answer & Solution
Correct answer: C. d³, paramagnetic with 3 unpaired e⁻
Cr³⁺: 3d³ (24 - 21 = 3 electrons in 3d after removing 3 from neutral Cr). In octahedral field: t2g³ (Hund's rule, all unpaired). 3 unpaired electrons → paramagnetic.
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