For [Cu(NH3)4(H2O)2]²⁺ (octahedral with 4 NH3 equatorial + 2 H2O axial…

Question

For [Cu(NH3)4(H2O)2]²⁺ (octahedral with 4 NH3 equatorial + 2 H2O axial), this is:

Accepted Answer

A. Trans isomer (the two H2O are on opposite ends)

With 4 identical NH3 in equatorial plane and 2 H2O on opposite ends (axial positions), the H2O ligands are trans to each other.
This is the trans isomer.
(Compare with cis where two H2O would be adjacent at 90 degrees.)

Answer

Random configuration

Answer

Cis isomer

Answer

Three isomers possible

For [Cu(NH3)4(H2O)2]²⁺ (octahedral with 4 NH3 equatorial + 2 H2O axial), this is:

Keep practising Unit 2B1: Transition Metals & Coordination Compounds