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For [Cu(NH3)4(H2O)2]²⁺ (octahedral with 4 NH3 equatorial + 2 H2O axial), this is:
ATrans isomer (the two H2O are on opposite ends)
BRandom configuration
CCis isomer
DThree isomers possible
Answer & Solution
Correct answer: A. Trans isomer (the two H2O are on opposite ends)
With 4 identical NH3 in equatorial plane and 2 H2O on opposite ends (axial positions), the H2O ligands are trans to each other. This is the trans isomer. (Compare with cis where two H2O would be adjacent at 90 degrees.)
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