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Hybridization in [Ni(CO)4] (Ni is 0 oxidation state, sp3 because CO is strong-field for Ni⁰):
Asp³d
Bdsp²
Csp³ (tetrahedral)
Dsp³d²
Answer & Solution
Correct answer: C. sp³ (tetrahedral)
Ni⁰ in [Ni(CO)4]: Ni has electronic config [Ar]3d⁸4s². CO is a strong-field pi-acceptor ligand. Forms a tetrahedral complex with sp³ hybridization (no d-orbitals used).
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