The complex [Fe(CN)6]⁴⁻ is:
AHexacyanoferrate(III)
BHexacyanoferrate(I)
CHexacyanoferrate(II)
DFerrocene
Answer & Solution
Correct answer: C. Hexacyanoferrate(II)
CN⁻ has charge -1. 6 CN⁻ contribute -6. Total complex charge -4. So Fe oxidation state: -4 = x + (-6) → x = +2. Fe²⁺. Named as hexacyanoferrate(II) (Roman numeral II for ox state).
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