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Number of unpaired electrons in [FeF6]³⁻ (high-spin, F⁻ weak-field):
A0
B5
C1
D3
Answer & Solution
Correct answer: B. 5
Fe³⁺ is d⁵. High-spin (F⁻ weak field): t2g³ eg² with all 5 unpaired (Hund's rule, single occupancy of all 5 d-orbitals). 5 unpaired electrons, very paramagnetic.
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