Oxidation state of Cr in [Cr(NH₃)₆]Cl₃:
A+1
B+6
C+3 (NH₃ neutral, 3 Cl⁻; sum must equal 0 → Cr = +3)
D+2
Answer & Solution
Correct answer: C. +3 (NH₃ neutral, 3 Cl⁻; sum must equal 0 → Cr = +3)
NH₃ is neutral, Cl⁻ is -1. [Cr(NH₃)₆]³⁺ × Cl₃ → Cr = +3. Common Cr(III) complex, octahedral, hexamine.
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