In a Wheatstone bridge, balance condition is:
- P/Q = R/S
- P · Q = R · S
- P + Q = R + S
- P/R = Q/S²
Show answer and solution
Correct answer: A. P/Q = R/S
1. At balance, galvanometer current = 0, so voltages at its two terminals are equal.
2. This gives the ratio condition P/Q = R/S.
3. Used in metre bridges to determine unknown resistance precisely.
_Source: syllabus Physics Ch 3 §3.10 Wheatstone Bridge_