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The drift velocity of electrons in a copper wire carrying steady current is of the order of

A{'text': '10⁻¹ m/s', 'label': 'A'}
B{'text': '10⁻⁴ m/s', 'label': 'B'}
C{'text': '10³ m/s', 'label': 'C'}
D{'text': '10⁸ m/s', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': '10⁻⁴ m/s', 'label': 'B'}
1. From v_d = -eEτ/m, drift velocity is proportional to field and relaxation time. 2. With typical current densities and free-electron density n ~ 10²⁸ m⁻³, |v_d| = I / (n e A). 3. For a copper wire this evaluates to about 10⁻⁴ m/s. 4. So drift velocity is remarkably small compared to thermal (~10⁶ m/s) or signal speeds. _Source: NCERT Class 12 Physics, Ch 3 "Current Electricity", §3.5_
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