In a Wheatstone bridge, arms have resistances P, Q, R, S in cyclic order with a galvanometer between the P-Q and R-S junctions. The bridge is balanced when
A{'text': 'P + Q = R + S', 'label': 'A'}
B{'text': 'P × S = Q × R', 'label': 'B'}
C{'text': 'P / Q = R / S', 'label': 'C'}
D{'text': 'P × Q = R × S', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'P / Q = R / S', 'label': 'C'}
1. In a Wheatstone bridge the galvanometer reads zero at balance.
2. The condition for zero galvanometer current is P / Q = R / S.
3. Equivalently P S = Q R (cross-product form).
4. Neither the sum condition nor P × Q = R × S is the balance criterion.
_Source: NCERT Class 12 Physics, Ch 3 "Current Electricity", §3 Wheatstone bridge_
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