In a Wheatstone bridge, balance condition is:

Question

Accepted Answer

A. P/Q = R/S

1. At balance, galvanometer current = 0, so voltages at its two terminals are equal.
2. This gives the ratio condition P/Q = R/S.
3. Used in metre bridges to determine unknown resistance precisely.
_Source: syllabus Physics Ch 3 §3.10 Wheatstone Bridge_

Answer

P · Q = R · S

Answer

P + Q = R + S

Answer

P/R = Q/S²

In a Wheatstone bridge, balance condition is:

Keep practising Current Electricity