In a Wheatstone bridge, balance condition is:
AP/Q = R/S
BP · Q = R · S
CP + Q = R + S
DP/R = Q/S²
Answer & Solution
Correct answer: A. P/Q = R/S
1. At balance, galvanometer current = 0, so voltages at its two terminals are equal.
2. This gives the ratio condition P/Q = R/S.
3. Used in metre bridges to determine unknown resistance precisely.
_Source: NCERT Class 12 Physics Ch 3 §3.10 Wheatstone Bridge_
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