A wire has a resistance R. It is stretched uniformly so that its length becomes 2L. The new resistance is
AR/4
BR/2
C4R
D2R
Answer & Solution
Correct answer: C. 4R
1. Stretching keeps volume V = A × L constant; if L doubles, A halves.
2. Original R = ρ L / A. New length L' = 2L, new area A' = A/2.
3. New R' = ρ (2L) / (A/2) = 4 ρ L / A = 4R.
4. So on doubling the length by stretching, resistance becomes four times.
_Source: syllabus Physics, Ch 3 "Current Electricity", §3.4_
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