alleryWhat is the standard enthalpy of fusion of ice?
- 40.79 kJ/mol
- 2.48 kJ/mol
- 44.01 kJ/mol
- 6.00 kJ/mol
Show answer and solution
Correct answer: D. 6.00 kJ/mol
Melting one mole of ice at 273 K absorbs 6.00 kJ.
NEET UG Thermodynamics — practice questions — page 2
Explore 95 free Thermodynamics questions in NEET UG Chemistry. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 31–60 of 95.
What is the standard enthalpy of fusion of ice?Read the answer and worked solution →Direct conversion of a solid into its vapour is called:Read the answer and worked solution →Why does acetone vaporise with less heat than water?Read the answer and worked solution →∆vapH of water at 298 K is 44.01 kJ/mol. Heat needed to evaporate 36 g of water?Read the answer and worked solution →With c = 4.2 J/g °C and ∆fusH = 6.00 kJ/mol, ∆H for 1 mol water at 50 °C to ice at 0 °C?Read the answer and worked solution →∆fH refers to forming one mole of a compound from:Read the answer and worked solution →The reference state of carbon used for enthalpies of formation is:Read the answer and worked solution →Why is ∆rH of CaO + CO2 → CaCO3 not ∆fH of CaCO3?Read the answer and worked solution →∆fH of HBr(g) is -36.4 kJ/mol. What is ∆rH for H2(g) + Br2(l) → 2HBr(g)?Read the answer and worked solution →With ∆fH (kJ/mol) CaCO3 -1206.9, CaO -635.1, CO2 -393.5, what is ∆rH for CaCO3 → CaO + CO2?Read the answer and worked solution →∆fH: H2O(l) -285.83, Fe2O3(s) -824.2 kJ/mol. Find ∆rH for Fe2O3 + 3H2 → 2Fe + 3H2O(l).Read the answer and worked solution →A balanced chemical equation written together with its ∆rH value is called a:Read the answer and worked solution →In a balanced thermochemical equation, the coefficients represent numbers of:Read the answer and worked solution →If N2 + 3H2 → 2NH3 has ∆rH = -91.8 kJ/mol, what is ∆rH for ½N2 + 3/2 H2 → NH3?Read the answer and worked solution →C + O2 → CO2 has ∆rH -393.5 and CO + ½O2 → CO2 has -283.0 kJ/mol. ∆rH for C + ½O2 → CO?Read the answer and worked solution →Why is ∆H of C + ½O2 → CO not measured directly?Read the answer and worked solution →Combustion reactions are, by nature:Read the answer and worked solution →Complete combustion of one mole of butane, the main gas in cooking cylinders, releases:Read the answer and worked solution →How much heat does the combustion of one mole of glucose give out?Read the answer and worked solution →Enthalpy of atomization refers to:Read the answer and worked solution →For a diatomic molecule like H2, the enthalpy of atomization equals its:Read the answer and worked solution →For Na(s) → Na(g), the enthalpy of atomization is the same as the enthalpy of:Read the answer and worked solution →The atomization enthalpy of CH4 is 1665 kJ/mol. What is the mean C-H bond enthalpy?Read the answer and worked solution →Among the four successive C-H bond breaks of methane, which step needs the least enthalpy?Read the answer and worked solution →For a gas-phase reaction, ∆rH can be estimated from bond enthalpies as:Read the answer and worked solution →Estimating ∆rH from mean bond enthalpies is valid only when all species are:Read the answer and worked solution →With H-H 435, Cl-Cl 242, H-Cl 431 kJ/mol, ∆rH for H2(g) + Cl2(g) → 2HCl(g) is:Read the answer and worked solution →Lattice enthalpy is the change when one mole of an ionic solid:Read the answer and worked solution →Lattice enthalpies are found indirectly using an enthalpy cycle named after:Read the answer and worked solution →A salt has lattice enthalpy +700 kJ/mol and hydration enthalpy -690 kJ/mol. Its ∆solH?Read the answer and worked solution →
Worked practice questions
Direct conversion of a solid into its vapour is called:
- Vaporisation
- Fusion
- Condensation
- Sublimation
Show answer and solution
Correct answer: D. Sublimation
Sublimation skips the liquid state, as with dry ice and naphthalene.
Why does acetone vaporise with less heat than water?
- Its boiling point is higher
- It has stronger H-bonding
- Its molecules are lighter
- Weaker dipole forces, not H-bonds
Show answer and solution
Correct answer: D. Weaker dipole forces, not H-bonds
Water molecules are held by strong hydrogen bonds, while acetone has only weaker dipole-dipole attractions.
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