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∆vapH of water at 298 K is 44.01 kJ/mol. Heat needed to evaporate 36 g of water?

A22.01 kJ
B176.0 kJ
C44.01 kJ
D88.02 kJ
Answer & Solution
Correct answer: D. 88.02 kJ
36 g of water is 2 mol, so the heat needed is 2 x 44.01 = 88.02 kJ.
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