With c = 4.2 J/g °C and ∆fusH = 6.00 kJ/mol, ∆H for 1 mol water at 50 °C to ice at 0 °C?
A-6.00 kJ
B-9.78 kJ
C-3.78 kJ
D+9.78 kJ
Answer & Solution
Correct answer: B. -9.78 kJ
Cooling gives -(18 x 4.2 x 50) J = -3.78 kJ and freezing gives -6.00 kJ, totalling -9.78 kJ.
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