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A salt has lattice enthalpy +700 kJ/mol and hydration enthalpy -690 kJ/mol. Its ∆solH?

A-10 kJ/mol
B+10 kJ/mol
C-1390 kJ/mol
D+1390 kJ/mol
Answer & Solution
Correct answer: B. +10 kJ/mol
∆solH = ∆latticeH + ∆hydH = 700 + (-690) = +10 kJ/mol.
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