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With ∆fH (kJ/mol) CaCO3 -1206.9, CaO -635.1, CO2 -393.5, what is ∆rH for CaCO3 → CaO + CO2?

A-2235.5 kJ/mol
B-178.3 kJ/mol
C+178.3 kJ/mol
D+2235.5 kJ/mol
Answer & Solution
Correct answer: C. +178.3 kJ/mol
∆rH = (-635.1) + (-393.5) - (-1206.9) = +178.3 kJ/mol, so the decomposition is endothermic.
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