allery∆fH: H2O(l) -285.83, Fe2O3(s) -824.2 kJ/mol. Find ∆rH for Fe2O3 + 3H2 → 2Fe + 3H2O(l).
A-538.4 kJ/mol
B-1681.7 kJ/mol
C-33.3 kJ/mol
D+33.3 kJ/mol
Answer & Solution
Correct answer: C. -33.3 kJ/mol
∆rH = 3(-285.83) - (-824.2) = -857.5 + 824.2 = -33.3 kJ/mol, with Fe and H2 taken as zero.
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