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Among the four successive C-H bond breaks of methane, which step needs the least enthalpy?

ACH2 → CH + H
BCH → C + H
CCH4 → CH3 + H
DCH3 → CH2 + H
Answer & Solution
Correct answer: B. CH → C + H
The last step, CH → C + H, needs only 347 kJ/mol against 427, 439 and 452 kJ/mol for the others.
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