If N2 + 3H2 → 2NH3 has ∆rH = -91.8 kJ/mol, what is ∆rH for ½N2 + 3/2 H2 → NH3?
A+45.9 kJ/mol
B-91.8 kJ/mol
C-45.9 kJ/mol
D-183.6 kJ/mol
Answer & Solution
Correct answer: C. -45.9 kJ/mol
Halving every coefficient halves the reaction enthalpy because enthalpy is extensive.
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