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M.Sc Biochemistry Named Reactions — practice questions

Explore 46 free Named Reactions questions in M.Sc Biochemistry Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Named Reactions questions and exercises with answers

Showing questions 1–30 of 46.

The product of the Hunsdiecker reaction on $CH_3CH_2COOAg$ with $Br_2/CCl_4$ isRead the answer and worked solution →In **Dow's process**, chlorobenzene is converted to phenol by treatment withRead the answer and worked solution →The **Finkelstein reaction** uses which solvent for the conversion $RCl \to RI$?Read the answer and worked solution →Why does the Finkelstein reaction proceed efficiently in acetone but not in water?Read the answer and worked solution →A **Grignard reagent** has the general formulaRead the answer and worked solution →The reaction of $CH_3MgBr$ with formaldehyde ($HCHO$), followed by acidic workup, givesRead the answer and worked solution →$CH_3MgBr$ reacts with $CO_2$ followed by acidic workup. The product isRead the answer and worked solution →Which solvent is essential for preparing a Grignard reagent and why?Read the answer and worked solution →The Lewis-acid catalyst typically used in **Friedel–Crafts alkylation** isRead the answer and worked solution →Benzene treated with $CH_3COCl$ and anhydrous $AlCl_3$ givesRead the answer and worked solution →Friedel–Crafts alkylation of benzene with $1$-chloropropane and $AlCl_3$ gives, as the major product,Read the answer and worked solution →The **Swarts reaction** converts an alkyl chloride to an alkyl fluoride usingRead the answer and worked solution →**Williamson's synthesis** of ethers couples an alkoxide withRead the answer and worked solution →In **Wurtz's reaction**, two alkyl halides couple in the presence ofRead the answer and worked solution →The Wurtz reaction on $CH_3CH_2Br$ with sodium in dry ether gives mainlyRead the answer and worked solution →The **Fittig reaction** couples two molecules ofRead the answer and worked solution →The Wurtz–Fittig reaction between $C_6H_5Br$ and $CH_3CH_2Br$ with Na in dry ether givesRead the answer and worked solution →**Lucas reagent** is a mixture ofRead the answer and worked solution →Among $1$-butanol, $2$-butanol and $tert$-butanol, the order of reactivity in the Lucas test isRead the answer and worked solution →**Kolbe's reaction** treats sodium phenoxide with $CO_2$ under pressure to giveRead the answer and worked solution →**Reimer–Tiemann reaction** of phenol with $CHCl_3$ and aq. $NaOH$, followed by hydrolysis, givesRead the answer and worked solution →The reactive electrophile in the Reimer–Tiemann reaction isRead the answer and worked solution →In the **cumene process** for industrial phenol production, the by-product formed alongside phenol isRead the answer and worked solution →For a carbonyl compound to undergo **aldol condensation**, it must haveRead the answer and worked solution →Self-aldol condensation of acetaldehyde, after dehydration, givesRead the answer and worked solution →A **cross aldol** condensation between benzaldehyde and acetone (excess acetone) gives, as the major product,Read the answer and worked solution →**Cannizzaro's reaction** is given by aldehydes that haveRead the answer and worked solution →**Rosenmund's reduction** converts an acyl chloride to an aldehyde usingRead the answer and worked solution →**Stephen's reduction** converts a nitrile $RCN$ into an aldehyde usingRead the answer and worked solution →In the **Etard reaction**, toluene is oxidised to benzaldehyde byRead the answer and worked solution →

Worked practice questions

The product of the Hunsdiecker reaction on $CH_3CH_2COOAg$ with $Br_2/CCl_4$ is

  1. $CH_3CH_2COBr$
  2. $CH_3Br$
  3. $CH_3CH_2Br$
  4. $CH_3CH_2CH_2Br$
Show answer and solution

Correct answer: C. $CH_3CH_2Br$

Hunsdiecker loses one carbon (as $CO_2$): $CH_3CH_2COOAg + Br_2 \to CH_3CH_2Br + CO_2 + AgBr$.

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In **Dow's process**, chlorobenzene is converted to phenol by treatment with

  1. $Br_2$ in $FeBr_3$
  2. $LiAlH_4$ in ether
  3. dil. $HCl$ at room temperature
  4. aq. $NaOH$ at $623\,K$, $300\,atm$
Show answer and solution

Correct answer: D. aq. $NaOH$ at $623\,K$, $300\,atm$

**Dow's process:** $C_6H_5Cl + NaOH \xrightarrow{623\,K, 300\,atm} C_6H_5ONa \xrightarrow{H^+} C_6H_5OH$. The harsh conditions are needed because the C–Cl bond in chlorobenzene has partial double-bond character (resonance) and resists nucleophilic substitution.

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The **Finkelstein reaction** uses which solvent for the conversion $RCl \to RI$?

  1. Benzene
  2. Acetone
  3. Water
  4. Ethanol
Show answer and solution

Correct answer: B. Acetone

$RCl + NaI \xrightarrow{acetone} RI + NaCl\downarrow$. Acetone dissolves NaI but precipitates NaCl, driving the equilibrium to the iodide by Le Chatelier's principle.

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