**Reimer–Tiemann reaction** of phenol with $CHCl_3$ and aq. $NaOH$, followed by hydrolysis, gives
ASalicylaldehyde
BBenzoic acid
CBenzaldehyde
DSalicylic acid
Answer & Solution
Correct answer: A. Salicylaldehyde
Reimer–Tiemann installs a $-CHO$ group ortho to phenol: $C_6H_5OH + CHCl_3 + NaOH \to o\text{-hydroxybenzaldehyde}$.
The reactive intermediate is dichlorocarbene $:CCl_2$.
Keep practising Aldehydes, Ketones and Carboxylic Acids
Browse all Aldehydes, Ketones and Carboxylic Acids questions for CBSE Class 12 (Science), or explore more Chemistry topics.
Related questions
Aldehydes and ketones, unlike alkenes, mainly undergo which kind of addition?Which reagent selectively reduces a nitrile to an imine that hydrolyses to an aldehyde?Which reagent oxidises hexan-1-ol to hexanal only?C8H8O gives 2,4-DNP and iodoform tests, not Tollens'. What is it?Which reagent reduces carboxylic acids to primary alcohols?Which reaction alpha-halogenates acids with Cl2 and red P?Why is SOCl2 preferred over PCl5 for converting RCOOH to RCOCl?Among Ph, Br, F and CF3, which substituent raises carboxylic acid strength the most?