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**Reimer–Tiemann reaction** of phenol with $CHCl_3$ and aq. $NaOH$, followed by hydrolysis, gives
ASalicylaldehyde
BBenzoic acid
CBenzaldehyde
DSalicylic acid
Answer & Solution
Correct answer: A. Salicylaldehyde
Reimer–Tiemann installs a $-CHO$ group ortho to phenol: $C_6H_5OH + CHCl_3 + NaOH \to o\text{-hydroxybenzaldehyde}$. The reactive intermediate is dichlorocarbene $:CCl_2$.
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