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**Kolbe's reaction** treats sodium phenoxide with $CO_2$ under pressure to give
APicric acid
BPhthalic acid
CSalicylic acid
DBenzoic acid
Answer & Solution
Correct answer: C. Salicylic acid
$C_6H_5ONa + CO_2 \xrightarrow{125\,°C,\,4\text{-}7\,atm} \text{sodium salicylate} \xrightarrow{H^+} \text{salicylic acid}$ (2-hydroxybenzoic acid). The reaction installs the carboxylate ortho to the phenoxide.
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