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Friedel–Crafts alkylation of benzene with $1$-chloropropane and $AlCl_3$ gives, as the major product,
An-Propylbenzene
B1,2-Dipropylbenzene
CCyclopropylbenzene
DIsopropylbenzene (cumene)
Answer & Solution
Correct answer: D. Isopropylbenzene (cumene)
The primary carbocation $CH_3CH_2CH_2^+$ rearranges (1,2-H shift) to the more stable secondary cation $(CH_3)_2CH^+$, which attacks benzene. Carbocation rearrangement is the classic Friedel–Crafts alkylation pitfall — acylation avoids this because acylium ions don't rearrange.
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