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In **Dow's process**, chlorobenzene is converted to phenol by treatment with
A$Br_2$ in $FeBr_3$
B$LiAlH_4$ in ether
Cdil. $HCl$ at room temperature
Daq. $NaOH$ at $623\,K$, $300\,atm$
Answer & Solution
Correct answer: D. aq. $NaOH$ at $623\,K$, $300\,atm$
Dow's process: $C_6H_5Cl + NaOH \xrightarrow{623\,K, 300\,atm} C_6H_5ONa \xrightarrow{H^+} C_6H_5OH$. The harsh conditions are needed because the C–Cl bond in chlorobenzene has partial double-bond character (resonance) and resists nucleophilic substitution.
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