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The **Swarts reaction** converts an alkyl chloride to an alkyl fluoride using
A$NaCl$
B$HBr$
C$KMnO_4$
D$AgF$ or $Hg_2F_2$
Answer & Solution
Correct answer: D. $AgF$ or $Hg_2F_2$
Swarts: $CH_3Cl + AgF \to CH_3F + AgCl$. Silver and mercurous fluorides are the textbook fluorinating agents because direct $F_2$ is too violent.
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