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The Wurtz–Fittig reaction between $C_6H_5Br$ and $CH_3CH_2Br$ with Na in dry ether gives
An-Butane
BBiphenyl
CEthylbenzene
DToluene
Answer & Solution
Correct answer: C. Ethylbenzene
Wurtz–Fittig: $C_6H_5Br + CH_3CH_2Br + 2\,Na \to C_6H_5-CH_2CH_3 + 2\,NaBr$. The mixed coupling between aryl and alkyl halides gives ethylbenzene as the desired product (with biphenyl and butane as side-products).
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