Home › UP Board Class 12 › chemistry › namedreactions › The product of the Hunsdiecker reaction on $CH_3…
The product of the Hunsdiecker reaction on $CH_3CH_2COOAg$ with $Br_2/CCl_4$ is
A$CH_3CH_2COBr$
B$CH_3Br$
C$CH_3CH_2Br$
D$CH_3CH_2CH_2Br$
Answer & Solution
Correct answer: C. $CH_3CH_2Br$
Hunsdiecker loses one carbon (as $CO_2$): $CH_3CH_2COOAg + Br_2 \to CH_3CH_2Br + CO_2 + AgBr$.
Related questions
Phenol is industrially manufactured by the **cumene process** instead of Dow's process becFriedel–Crafts **acylation** is generally preferred over alkylation for installing a $-R$ Which aldehyde would NOT undergo aldol condensation but WOULD undergo Cannizzaro?Identify the correct conversion: $CH_3CN \xrightarrow{?} CH_3CHO$ (one step).Which of the following named reactions does **NOT** require an $\alpha$-hydrogen on the suThe **Balz–Schiemann reaction** converts $ArN_2^+$ to $ArF$ via which intermediate?The **Gattermann reaction** (not Gatterman–Koch) converts $ArN_2^+X^-$ to $ArX$ usingSandmeyer's reaction proceeds via which type of intermediate?